10x^2-10x-560=0

Solution for 10x^2-10x-560=0 equation:

10x^2-10x-560=0

a = 10; b = -10; c = -560;
Δ = b2-4ac
Δ = -102-4·10·(-560)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-150}{2*10}=\frac{-140}{20}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+150}{2*10}=\frac{160}{20}
=8
$